Is There an Operation that Reverses the "cmc()" Function?

Reality Glitch 2/2 Zombie Posts: 107 Color Alignment: White, Blue, Red, Green, Colorless	Is There an Operation that Reverses the "cmc()" Function? Nov 22, 2023 1:33:06 GMT Quote Select Post Deselect Post Link to Post Member Give Gift Back to Top Post by Reality Glitch on Nov 22, 2023 1:33:06 GMT i.e. Conversely to how "cmc()" takes a set of symbols and counts how many there are (e.g. "" becomes "3"), is there one that would allow me to have "Manaburst 3 (When this dies, add .)"?

cajun 20/20 Avatar i write tragedies not sins Posts: 2,219 Set Hub: Cajun's Explorations Favorite Card: Mirrorweave Color Alignment: Blue, Green	Is There an Operation that Reverses the "cmc()" Function? Nov 22, 2023 12:19:22 GMT Quote Select Post Deselect Post Link to Post Member Give Gift Back to Top Post by cajun on Nov 22, 2023 12:19:22 GMT `number := 3 symbols := for x from 1 to number do "[W]"; # symbols == "[W][W][W]"`
	Cygari Monsters of Chikyu - On Layers - Cajun Style Templates "I dunno, Cajun has a habit of doing Dubiously Working new rules stuff" —fluffyDeathbringer

Reality Glitch
2/2 Zombie

Posts: 107
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Is There an Operation that Reverses the "cmc()" Function? Nov 23, 2023 2:57:04 GMT

Quote

number := 3
symbols := for x from 1 to number do "[W]";
# symbols == "[W][W][W]"

Thank you! I know this all sounds like basic stuff I need explained.

Last Edit: Nov 24, 2023 18:59:12 GMT by Reality Glitch