Post by galva94 on Jul 23, 2020 17:46:02 GMT
This is not exactly a question about a card, but I hope this is the proper place to post.
My problem is the following: I would like to make a set and print it out, but I am not sure of how to balance the number of cards with respect to rarity. Let me explain with an example.
Let say I have a set with 101 commons, 80 uncommons, 53 rares and 15 mythic, which is more or less the standard set size. Let's consider the mythic to be as frequent as the rares for sake of semplicity (i.e. lets say we have 68 rares). To print this set and play it with friends as it would be an official set I would have to print out... ready..? 19040 cards! (If I get the math right!). And I would have to print out: 136 copies of each common, 51 copies of each uncommon and 20 of each rare and mythic. (Actually i considered 100 unique commons instead of 101, again for sake of semplicity). Math nerds can check that 136*100 + 51*80 + 20*68 = 19040, and with this pool we can create 1360 booster packs with the right amount of cards or each rarity.
Of course there's only a small issue: there is no way that this crazy amount of prints will ever be used!
One way this numbers can be taken down is to adapt the size of the set (i.e number of cards per rarity) such that they are "less coprime" in some sense, and more similar to the booster pack ratio 10:3:1. Maybe later I'll try to figure out some optimal sizes, but I doubt we can go under 1000 cards. Ideally I would like to print something like 336 cards (ideal for a 8 people draft of 14 cards/pack).
The number of commons, uncommon and rares for my purpose can be very flexible, so I can accept a solution that contemplate an unusual number of cards per rarirty, if it works!
An approach that I thought about is to print like 3 copies of each common, 2 copies of each uncommon and 1 copy of each rare/mythic with a set of 80c*3copies+36u*2copies+24r*1copy = 336 cards. In this way all cards are played in a 8-player draft: infact
My problem is the following: I would like to make a set and print it out, but I am not sure of how to balance the number of cards with respect to rarity. Let me explain with an example.
Let say I have a set with 101 commons, 80 uncommons, 53 rares and 15 mythic, which is more or less the standard set size. Let's consider the mythic to be as frequent as the rares for sake of semplicity (i.e. lets say we have 68 rares). To print this set and play it with friends as it would be an official set I would have to print out... ready..? 19040 cards! (If I get the math right!). And I would have to print out: 136 copies of each common, 51 copies of each uncommon and 20 of each rare and mythic. (Actually i considered 100 unique commons instead of 101, again for sake of semplicity). Math nerds can check that 136*100 + 51*80 + 20*68 = 19040, and with this pool we can create 1360 booster packs with the right amount of cards or each rarity.
Of course there's only a small issue: there is no way that this crazy amount of prints will ever be used!
One way this numbers can be taken down is to adapt the size of the set (i.e number of cards per rarity) such that they are "less coprime" in some sense, and more similar to the booster pack ratio 10:3:1. Maybe later I'll try to figure out some optimal sizes, but I doubt we can go under 1000 cards. Ideally I would like to print something like 336 cards (ideal for a 8 people draft of 14 cards/pack).
The number of commons, uncommon and rares for my purpose can be very flexible, so I can accept a solution that contemplate an unusual number of cards per rarirty, if it works!
An approach that I thought about is to print like 3 copies of each common, 2 copies of each uncommon and 1 copy of each rare/mythic with a set of 80c*3copies+36u*2copies+24r*1copy = 336 cards. In this way all cards are played in a 8-player draft: infact
- 10 * 24boosters = 80 * 3copies
- 3 * 24boosters = 36 * 2copies
- 1 * 24boosters = 24* 1copy
The problem here is that the proportons are completely gone! 101 : 80 : 68 is VERY different from 80 : 36 : 24 (especially the gam between commons and uncommons!)
I am really curious to know how you guys tackled this problem, because searching online I haven't found much! Again, I don't care if the solution is not perfect, as long as it works with small numbers.
Sorry for the math, but I decided to post it because maybe someone will find it interesting.
I am really curious to know how you guys tackled this problem, because searching online I haven't found much! Again, I don't care if the solution is not perfect, as long as it works with small numbers.
Sorry for the math, but I decided to post it because maybe someone will find it interesting.